Question

integrate 1/(e^x-1)^2​

Answer 1

Answer:

1/2(e^x-1)ln(e^x-1)^2+c

Step-by-step explanation:

Put (e^x-1)=t

=2(e^x-1)dx=dt

=dx=dt/2(e^x-1)

=In( 1/t dt/2(e^x-1)

=1/2(e^x-1)ln(e^x-1)^2+c

Pls tell if my ans is correct or not??