Question

Integrate 1/e^x pls help me with this

Answer 1

Answer:

$\frac{dy}{dx} = -e^{-x} = \frac{-1}{e^x}$

Step-by-step explanation:

$\frac{1}{e^x}$

Now we can write it as $e^{-x}$.

Let $y = e^{-x}$

Differentiating with respect to x,

dy/dx = d/dx (e^(-x))

Math help : d/dx (e^x) = e^x.

Apply chain rule for above expression,

( Example : d/dx (f(g(x)) = f¹(g(x))g¹(x) )

dy/dx = e^(-x) (d/dx (-x))

dy/dx = - e^(-x) = -1/e^x. Wait I would put up equation.

$\frac{dy}{dx} = -e^{-x} = \frac{-1}{e^x}$.