integrate 1/x^5*(1-x^7)
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Answered by
7
ne way to look at the problem is to say that it would be easy if the integrand were
7x6−1x7−x,
and also easy if it were
x6−1x7−x.
Now take a linear combination of these to knock out the x6 term in the numerator.
Answered by
10
Answer:
I=∫dxx(x7+1)I=∫dxx(x7+1)
=∫dxx8+x=∫dxx8+x
=∫dxx8(1+1x7)=∫dxx8(1+1x7)
u=1+1x7⟹du=−7dxx8⟹−du7=dxx8u=1+1x7⟹du=−7dxx8⟹−du7=dxx8
I=−17∫1uduI=−17∫1udu
=−ln(u)7=−ln(u)7
=−ln(1+1x7)7+c
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