Question

INTEGRATE..................

Answer 1

Given equation:

(x+2)(x+3)+(x-3)(x-2)-2x(x+1)=0

=> x²+3x+2x+6+x²-2x-3x+6-2x²-2x=0

=> x²+5x+6+x²-5x+6-2x²-2x=0

=> x²+x²-2x²+5x-5x-2x+6+6=0

=> -2x+12=0

=> -2x=-12

=> x = (-12)/(-2)

=> x = 6

Therefore,

x=6

Answer 2

see the attachment!!!!!