Question

Integrate ʃ π/2Cosxdx​

Answer 1

Answer:

I = int0^pi/2 cosx dx = [sinx]0^pi/2 = [sin pi2 - sin0] = 1

Answer 2

$\displaystyle \large \bf I=∫ _0 ^{π/2} cosx \: dx \\ \\ \displaystyle \large \bf I =[sinx] _0^{π/2} \\ \\ \displaystyle \large \bf I =[sin \frac{π}{2} −sin0] \\ \\ \boxed{\displaystyle \huge \bf I = 1}$