Math, asked by Viole, 1 year ago

Integrate: (2x^3+3x-7)/(x^[2/3])

Answers

Answered by kvnmurty
2
(2 x³ + 3 x - 7) / (x²/³)
=\int {2 x^{\frac{7}{3}}+3 x^{\frac{1}{3}}-7 x^{-\frac{2}{3}}} \, dx\\\\=2*\frac{3}{9}x^{\frac{10}{3}}+3 *\frac{3}{4}x^{\frac{4}{3}}-7*\frac{1}{3}x^{\frac{1}{3}}+K
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