CBSE BOARD XII, asked by vijaydhawal20091975, 1 month ago

integrate (2x-3)/√x²+4x+8

Answers

Answered by lakojurmr

0

Answer:

(2x-3)/√x²+4x+8=-0.07x

Explanation:

(2x-3)/√x²+4x+8

= -1x/x+4x+8

= -1x/x+12x

= -1x/13x

=-0.07x

hope it is helpful.

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