integrate
(3t^2-2t)dt
Answers
Answered by
18
Step-by-step explanation:
Integration of 3t²-2t
=3integrate t² dt-2integratex
=3(t³/3)-2(t²/2)
=t³-t² +c
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Answered by
2
Given : ∫(3t² - 2t)dt
To Find : Evaluate the integral
Solution:
∫(3t² - 2t)dt
= ∫3t²dt - ∫2tdt
= 3∫t²dt - 2∫tdt
∫xⁿ = ( xⁿ⁺¹) /(n + 1) + C
= 3t³/3 - 2t²/2 + C
= t³ - t² + C
∫(3t² - 2t)dt = t³ - t² + C
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