Question

Integrate (4x ^ 6 + 3x ^ 5 + 2x ^ 4 + x ^ 3 + x ^ 2 + 1)/(x ^ 3)​

Answer 1

Answer:

x^4 + x^3 + x + lnx - x^(-2)/2 +c

Step-by-step explanation:

at frist I simply that equation

= 4x^6/x^3 + 3x^5/x^3 + x^3/x^3 + x^2/x^3 + 1/x^3

=4x^3 + 3x^2 + 1 + x^(-1) + x^(-3)

= Integrate (4x^3 + 3x^2 + 1 + x^(-1) + x^(-3))

= 4 × x^4/4 + 3 × x^3/3 + x + lnx + x^(-2)/(-2) +c

= x^4 + x^3 + x + lnx - x^(-2)/2 +c