Math, asked by Deepsharan, 8 months ago

integrate 5x*✓1-2x^2​

Answers

Answered by ravindrabansod26
6

Answer:

Step-by-step explanation:

∫(x√1+2x^2)dt\\Let \\u = 1 + 2x^2du\\ = 4x dxdx\\ = du/4x∫(x√1+2x^2)dx\\ = ∫x * u^1/2*du/4x\\= ∫u^1/2/4 du\\= 1/4∫u^1/2 du\\= 1/4 ( 2/3 u^3/2) + C\\= 1/6 (1 + 2x^2)^3/2 + C

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