Question

integrate cos(log x^2)/x^4 dx​

Answer 1

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Answer 2

Answer:

The result is $I=sin(logx)+c$.

Step-by-step explanation:

We are given with the integral $I=\int {\frac{cos(logx)}{x} } \, dx$

An integral assigns numbers to functions in a way that describes displacement, area, volume.

Logarithm function is is an exponent. We can write exponential expression can be rewritten in logarithmic form.

The cosine function in a triangle is the ratio of the adjacent side to that of the hypotenuse.

Using $logx=t$

Differentiating both sides,

$\frac{dx}{x} =dt$

Integral becomes $I=\int{cost} \, dt$

$I=sint+c$

$I=sin(logx)+c$

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