Math, asked by rishu8012, 1 year ago

Integrate cosec^2x -2005/cos^2005x dx


zagreb: Please post the image of the question as the exponents are confusing

Answers

Answered by rohitkumargupta
93

HELLO DEAR,

GIVEN FUNCTION IS:-\bold{\int{\frac{cosec^2x - 2005}{cos^{2005}x}}\,dx}

\bold{\int{[\frac{cosec^2x}{cos^{2005}x} - \frac{2005}{cos^{2005}x}]}\,dx}

∴ [integrating by parts]

\bold{\frac{1}{cos^{2005}x}\int{cosec^2x}\,dx - \int{[d(sec^{2005}x)/dx*\int{cosec^2x}\,dx]}\,dx - \int{\frac{2005}{cos^{2005}x}}\,dx}

\bold{\frac{1}{cos^{2005}x}(-cotx) - \int{(2005*sec^{2004}xsecxtanx*(-cotx))}\,dx - \int{\frac{2005}{cos^{2005}x}}\,dx}

\bold{\frac{1}{cos^{2005}x}(-cotx) + \int{\frac{2005}{cos^{2005}x}}\,dx - \int{\frac{2005}{cos^{2005}x}}\,dx}

\bold{-\frac{cotx}{cos^{2005}x} + c}

\bold{\large{HENCE, \int{\frac{cosec^2x - 2005}{cos^{2005}x}}\,dx = -\sf{\frac{cotx}{cos^{2005}x} + c}}}

I HOPE ITS HELP YOU DEAR,
THANKS


CBSEMP: superb
CBSEMP: nice explained
rohitkumargupta: thanks to everyone
princess108: nice ans
FuturePoet: Well done !!!
rohitkumargupta: :-)
rohitkumargupta: xi + yj + constant
rohitkumargupta: thanks
Similar questions