Question

Integrate \displaystyle \int \tt{e}^{ - x} \: dx \: for \bigg[0, \infty \bigg]∫e −x dxfor[0,∞] ​

Answer 1

Answer:

Step-by-step explanation:

We have,

$\tt{\displaystyle\int\limits^{\infty}_{0}{e}^{-x}\,dx}$

$\tt{=\left[\dfrac{{e}^{-x}}{-1}\right]^{\infty}_{0}}$

$\tt{=-\left[{e}^{-x}\right]^{\infty}_{0}}$

$\tt{=-[{e}^{-\infty}-{e}^{0}]}$

$\tt{=-[0-1]}$

$\tt{=1}$

Answer 2

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