Question

integrate✔✔

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Answer 1

Step-by-step explanation:

Evaluate [cos-¹x{√(1-x²)}]-¹/loge{1+(sin(2x(√1-x²)/π)}

∫fg′=fg−∫f′g

f =arccos(x), g′ =x/√1−x^2

f′ =−1/√1−x2, g =−√1−x2

= −√1−x2arccos (x)−∫1 dx

Now solve: ∫1 dx, apply constant rule: =x

Plug in our solved integrals:

−√1−x2arccos(x)−∫1dx =−√1−x2arccos(x)−x

Thus the answer is:

−√1−x2arccos(x)−x+C

Answer 2

Answer:

please see in the attachment