Integrate
dx/a+bcoshx
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Answered by
0
Answer:
what?
Step-by-step explanation:
Answered by
3
Answer:
Step-by-step explanation:
There are three cases here.
|a|>|b|
let c=(a^2-b^2).
The result is then (2/c)*arctan(c*tan(x/2))/(a+b)
+C
2. |a|<|b|
let c=sqrt(b^2-c^2)
The result is then
(1/c)*ln((c*tan(x/2)+a+b)/(c*tan(x/2) -a -b)) +C
3. a=b
If you replace 1 +cos(x) with (sin(x/2))^2 the integral reduces to integral of
dx/(sin(x/2))^2. This is a standard integral.
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