Math, asked by veerveersingh74, 5 months ago

integrate dx / xroot ofx^2-X +3​

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Answered by shauryasingh310
0

Answer:

∫(x+2)√(x-3)dx

∫(x+2)√(x-3)dxIntegration by parts

∫(x+2)√(x-3)dxIntegration by partsTake (x+2) as a first function & (x-3)^1/2 as a second function

∫(x+2)√(x-3)dxIntegration by partsTake (x+2) as a first function & (x-3)^1/2 as a second function(x+2).1÷2((x-3)^3/2)÷3/2) −∫1. 1÷2 ((x−3)3/2)÷3/2)dx

∫(x+2)√(x-3)dxIntegration by partsTake (x+2) as a first function & (x-3)^1/2 as a second function(x+2).1÷2((x-3)^3/2)÷3/2) −∫1. 1÷2 ((x−3)3/2)÷3/2)dx (1÷2)*2÷3(x+2).(x-3)^3/2 −(2÷3 ) ∗(1÷2)∫(x−3)3/2dx

∫(x+2)√(x-3)dxIntegration by partsTake (x+2) as a first function & (x-3)^1/2 as a second function(x+2).1÷2((x-3)^3/2)÷3/2) −∫1. 1÷2 ((x−3)3/2)÷3/2)dx (1÷2)*2÷3(x+2).(x-3)^3/2 −(2÷3 ) ∗(1÷2)∫(x−3)3/2dx 2 cancel with 2 ..

∫(x+2)√(x-3)dxIntegration by partsTake (x+2) as a first function & (x-3)^1/2 as a second function(x+2).1÷2((x-3)^3/2)÷3/2) −∫1. 1÷2 ((x−3)3/2)÷3/2)dx (1÷2)*2÷3(x+2).(x-3)^3/2 −(2÷3 ) ∗(1÷2)∫(x−3)3/2dx 2 cancel with 2 ..1÷3(x+2).(x-3)^3/2 −1÷3.((x−3)5/2)÷52+c

∫(x+2)√(x-3)dxIntegration by partsTake (x+2) as a first function & (x-3)^1/2 as a second function(x+2).1÷2((x-3)^3/2)÷3/2) −∫1. 1÷2 ((x−3)3/2)÷3/2)dx (1÷2)*2÷3(x+2).(x-3)^3/2 −(2÷3 ) ∗(1÷2)∫(x−3)3/2dx 2 cancel with 2 ..1÷3(x+2).(x-3)^3/2 −1÷3.((x−3)5/2)÷52+c Where c is integration constant

∫(x+2)√(x-3)dxIntegration by partsTake (x+2) as a first function & (x-3)^1/2 as a second function(x+2).1÷2((x-3)^3/2)÷3/2) −∫1. 1÷2 ((x−3)3/2)÷3/2)dx (1÷2)*2÷3(x+2).(x-3)^3/2 −(2÷3 ) ∗(1÷2)∫(x−3)3/2dx 2 cancel with 2 ..1÷3(x+2).(x-3)^3/2 −1÷3.((x−3)5/2)÷52+c Where c is integration constantAnswer

∫(x+2)√(x-3)dxIntegration by partsTake (x+2) as a first function & (x-3)^1/2 as a second function(x+2).1÷2((x-3)^3/2)÷3/2) −∫1. 1÷2 ((x−3)3/2)÷3/2)dx (1÷2)*2÷3(x+2).(x-3)^3/2 −(2÷3 ) ∗(1÷2)∫(x−3)3/2dx 2 cancel with 2 ..1÷3(x+2).(x-3)^3/2 −1÷3.((x−3)5/2)÷52+c Where c is integration constantAnswer1÷3(x+2).(x-3)^3/2 −2÷15.(x−3)5/2+c

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