Question

Integrate e^2x/(1+e^x)

Answer 1

Let I =∫e2xdx1+ex let 1+ex=t⇒exdx=dtNow, I =∫e2xdx1+ex=∫exex+1 . exdx = ∫(t−1)dtt=∫(1−1t)dt=t−log t+C=(1+ex)−log(1+ex)+C