integrate e^6y.y^2 dy
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Step-by-step explanation:
M∂y = ∂2I∂y ∂x
∂N∂x = ∂2I∂y ∂x
they end up the same! And so this will be true:
∂M∂y = ∂N∂x
When it is true we have an an "exact equation" and we can proceed.
And to discover I(x, y) we do EITHER:
I(x, y) = ∫M(x, y) dx (with x as an independent variable), OR
I(x, y) = ∫N(x, y) dy (with y as an independent variable)
And then there is some extra work (we will show you) to arrive at the general solution I think it had helped you
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