Question

integrate √(e^x-1)dx
please help me to solve this

Answer 1

1. let e^x-1=t

2. dt=e^xdx

3.dt=(t+1)dx

4. substitute dx as dt/(t+1)

5. the term becomes-( (√t)/t+1)dt

6. write denominator as (√t)^2+1

7. put √t=y

you will get the answer by simple formulas now.