Integrate it 1/cos²x(1-tanx)²
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Answer:
1/(1 - tan x) + C
Step-by-step explanation:
Given:
1/cos²x(1 - tanx)²
Let,
t = 1 - tan x
dt = sec²x dx
= (1/cos² x) dx
= (dx/cos² x)
Now,
On integrating we get,
∫ t⁻² dt
= (1/t) + C
= (1/1 - tanx) + C
Hope it helps!
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Answer:
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