Question

integrate it wrt x
also pls attempt only if you know how to solve it.....

Answer 1

this is a great integrated

Answer 2

$\int\ {sin^{4}x } \, dx$
=$\int\ ( { \frac{1-cos 2x}{2}) }^{2} \, dx$
=$\frac{1}{4} \int\ {(1- cos 2x + cos^{2}x }) \, dx$
=$\frac{1}{4} [x - \frac{2 six 2x}{2} + \int\ { \frac{(1+ cos 4x)}{2} } \, dx ]$
=$\frac{1}{4} [x- sin 2x + \frac{1}{2} (x + \frac{sin 4x}{4} )] +c$

After this open brackets 
Hope this helps