Question

Integrate [log(log x)]/x​

Answer 1

Hey there!

I = ∫ log (log x) / x

Let log x = t

and, 1 /x. dx = dt

I = ∫ log t.dt

=  ∫ log t. 1 dt

= logt. ∫ 1.dt - ∫ 1/t. t dt

= t logt - ∫ dt

= t log t - ( t + C)

= t logt - t + C

I= logx ( log log(x) - 1) + C

Answer 2

Answer;

logx [log(logx)] - logx + C

Step-by-step explanation:

Hey Buddy,

Now simply Put the Value of t ,

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