integrate logy by x dx
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as integration with dx y should be independent of x
so bring logy out of integration and integrate 1byx dx
which gives logx × logy
so bring logy out of integration and integrate 1byx dx
which gives logx × logy
Answered by
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on considering y independent of X
∫logy/x dx
= logy ∫1/x dx
= log y log |X| +c
where c is an arbitrary constant
∫logy/x dx
= logy ∫1/x dx
= log y log |X| +c
where c is an arbitrary constant
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