Question

integrate sec x /secx +tanx

Answer 1

[tex]\ \ \ \int ({ \frac { \sec x }{ \sec x + \tan x } }) dx \\ = \int { \frac{ \sec x ( \sec x - \tan x ) }{ \sec ^2 x - \tan ^2 x } } dx \\ = \int { ( \sec ^2 x - \sec x .\tan x ) } dx \\ = \tan x - \sec x + c[/tex]