Question

Integrate Sec2x tan2x/(sec2x + tan2x)

Answer 1

Integral sec2x tan2x dx let u = 2x and du = 2 dx so du/2 = dx so the new integral is (1/2)Integral sec u tan u du and we know that the derivative of secu = secu tan u and we know that the integral is just the anti of a derivative so the answer is sec u / 2 + c but we have to sub our 2x back in so we get (Sec2x)/2 + C