Math, asked by vsinghthakur, 1 year ago

integrate (sin^2x-cos^2x)/sinx.cosx

brunoconti: resend for a solution. the solution från virtuoso is wrong

Answers

Answered by shreyanshgupta9

Hello user !

Answer :-( sin^2x - cos ^2x)/sinx* cosx

We know that sin^2 x = cos^x-1

So , using vale of sin^2x in above question.

Therefore,( cos^2x -1 - cos^2 x )/since*cosx

cos^2x will get cancelled.

-1 / cosx * sin x

sinx = 1/ cosec x and cos x= 1/ secx

so , The answer will be :. - cosecx * secx

Hope it helps ❤ ❤

vsinghthakur: but its answer is -log|sin2x|+C

shreyanshgupta9: Brother..there are many ways to intergrate ...so this is absolutely possible

vsinghthakur: thnxx alot brother

brunoconti: wrong answer. resend for a solution

shreyanshgupta9: whose answer is wrong.

shreyanshgupta9: mine??

brunoconti: yeah because the log function is involved.

shreyanshgupta9: Yaah sir..sorry to say..but the user's question was to intergrate ..meaning to combine...So the method i knew i did

Answered by brunoconti

Answer:

Step-by-step explanation:

Attachments:

brunoconti: thks

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