Question

integrate sin (a+b log x)/x

Answer 1

Answer:

∫sinlnxx3dx

∫sinlnxxe2lnxdx

lnx=u

1xdx=du

∫e−2usinudu

−e−2ucosu−2∫e−2ucosudy

∫e−2usinudu=−e−2ucosu−2(e−2usinu+2∫e−2usinudu)

5∫e−2usinudu=−e−2ucosu−2e−2usinu

∫e−2usinudu=−15e−2ucosu−25e−2usinu

−15e−2lnxcoslnx−25e−2lnxsinlnx

−coslnx5x2−2sinlnx5x2+C

Answer 2

Step-by-step explanation:

Refer to the attachment..