Question

integrate sin(log x)÷x

Answer 1

put logx = t
therefore 1/ x * dx= dt
therefore
$ln(sin(t) dt$
= - cos t = - cos(logx) + c

Answer 2

Answer:

cos(logx) + c

Step-by-step explanation:

Assume,

⇒ logx = t  

⇒ d(logx) = dt  

⇒ $\frac{1}{x}$ dx = dt

⇒ Substituting t and dt

⇒  ∫sint dt

⇒ - cost + c  

But,

t = logx  

⇒ cos(logx) + c.