Question

Integrate sin²x.cos²x

Answer 1

Answer: $\frac{sin^3 x}{3} - \frac{sin^5 x}{5} + c$

Step-by-step explanation:

∫sin^2 x . cos^2 x dx

=∫sin^2 x . (1-sin^2 x) dx

=∫sin^2 x - sin^4 x dx

=sin^3 x/3 - sin^5/5 + c

Answer 2

Answer:

ok not thanks to help 3 others