Question

integrate (sin⁴x+cos⁴x)/(sin³x+cos³x)

Answer 1

Answer:

Step-by-step explanation:

As per the identities,

a³ + b³ = (a + b)(a² - ab + b²).

Put a = sin x , b = cos x

So,

sin³ x + cos³ x = (sin x + cos x)(sin² x - sin x.cos x + cos²x).

Since, sin² x + cos² x = 1.

So,

sin³ x + cos³ x = (sin x + cos x)(1- sin x.cos x).

Hope it helped you!

Answer 2

Answer:

sin⁴x.cos³x

integrate this function with respect to x