integrate (sin⁴x+cos⁴x)/(sin³x+cos³x)
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Answer:
Step-by-step explanation:
As per the identities,
a³ + b³ = (a + b)(a² - ab + b²).
Put a = sin x , b = cos x
So,
sin³ x + cos³ x = (sin x + cos x)(sin² x - sin x.cos x + cos²x).
Since, sin² x + cos² x = 1.
So,
sin³ x + cos³ x = (sin x + cos x)(1- sin x.cos x).
Hope it helped you!
Answered by
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Answer:
sin⁴x.cos³x
integrate this function with respect to x
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