Math, asked by priyanshujain2222, 1 year ago

integrate (sin⁴x+cos⁴x)/(sin³x+cos³x)

Answers

Answered by dharsansri672007
0

Answer:

Step-by-step explanation:

As per the identities,

a³ + b³ = (a + b)(a² - ab + b²).

Put a = sin x , b = cos x

So,

sin³ x + cos³ x = (sin x + cos x)(sin² x - sin x.cos x + cos²x).

Since, sin² x + cos² x = 1.

So,

sin³ x + cos³ x = (sin x + cos x)(1- sin x.cos x).

Hope it helped you!

Answered by anjanaatar123
0

Answer:

sin⁴x.cos³x

integrate this function with respect to x

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