Question

Integrate Sinx /(1-cos x)(2-3cosx)

Answer 1

Step-by-step explanation:

Let

u=2+3cosx

du=−3sinxdx

sinxdx=−13du

Therefore,

∫sinxdx(2+3cosx)2=−13

∫duu2=−13

∫u−2du=13⋅1u=13⋅(12+3cosx)+C