integrate sqrt(1 + x) dx =
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EXPLANATION.
⇒ ∫√(1 + x) dx.
As we know that,
Using substitution method in this equation, we get.
Let, we assume that.
⇒ 1 + x = t².
Differentiate w.r.t x, we get.
⇒ dx = 2tdt.
Put the values in the equation, we get.
⇒ ∫√(t²) 2tdt.
⇒ ∫t.2tdt.
⇒ ∫2t²dt.
⇒ 2(t³)/3 + c.
Put the value of t = √(1 + x) in the equation, we get.
⇒ 2[√(1 + x)]³/3 + c.
MORE INFORMATION.
(1) ∫0.dx = c.
(2) ∫1.dx = x + c.
(3) ∫k dx = kx + c, (k ∈ R).
(4) ∫xⁿdx = xⁿ⁺¹/n + 1 + c, ( n ≠ - 1).
(5) ∫dx/x = ㏒(x) + c.
(6) ∫eˣdx = eˣ + c.
(7) ∫aˣdx = aˣ/㏒(a) + c = aˣ㏒(e) + c.
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