integrate √tan x/sin x cos x
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Answered by
0
Answer:
2√tanx +C
Step-by-step explanation:
The answer is
=
2
√
tan
x
+
C
Explanation:
We need
tan
x
=
sin
x
cos
x
sin
x
=
cos
x
tan
x
=
tan
x
sec
x
Therefore, the integral is
I
=
∫
√
tan
x
d
x
sin
x
cos
x
=
∫
√
tan
x
d
x
tan
x
sec
x
⋅
1
sec
x
=
∫
sec
2
x
d
x
√
tan
x
Let
u
=
tan
x
,
⇒
,
d
u
=
sec
2
x
d
x
The integral is
I
=
∫
(
d
u
)
√
u
=
√
u
1
2
=
2
√
u
=
2
√
tan
x
+
C
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