Integrate the following
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Answer:
log [ e^x + e^(-x) ]
Step-by-step explanation:
we know that....
$ [ f'(x)/f(x) ] dx = log (f(x))
here....
f(x) = e^x + e^(-x) and f'(x) = e^x - e^(-x)
therefore...the integrattoon is...
log [ e^x + e^(-x) ]
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