Integrate the following w.r.tx., (2x+5)^8+ (7-3x)^9
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Answer:
The answer of the question is ((2x+5)^9)/18-((7-3x)^10)/30
Step-by-step explanation:
∫(2x+5) ^8dx+∫(7-3x) ^9dx
Put, 2x+5=z and 7-3x=u
Then, 2dx=dz and -3dx=du
This implies dx=dz/2 and dx=du/-3
1/2∫z^8dz -1/3∫u^9du
=1/2[z^9/9]-1/3[u^10/10]
Putting the value of z and u, we get,
(2x+5) ^9/18 - (7-3x)^10/30
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