integrate the following with solution
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On differentiating tanx you get sec²x, thus on integrating sec²x you'll get tanx.
So putting limits π/4 and 0, you get
tan(π/4) - tan(0) = 1-0=1
So putting limits π/4 and 0, you get
tan(π/4) - tan(0) = 1-0=1
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