integrate the following- (x-2)^2 √x
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Answer:
integration(x^2+x^2-2x*√x)dx
intergal of ( x^2*x^1/2+4*x^1/2-2*x^1/2+1)dx
integral of( x^5/2+4^1/2-2*x^3/2)dx
result
will be
l= 2/7x^7/2+8/3*x^3/2-5*x5/2
Step-by-step explanation:
1. we have opened whole sq of (a-b)^2
2.multiplying √2by (x-2)^2
3.l=a^n+1/n+1 is the formula used.
4. then is the end result.
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