Question

integrate the function cos√x/√x .dx

Answer 1

this is answer ........

Answer 2

$\bf{\int{\frac{cos\sqrt{x}}{\sqrt{x}}},dx}$
Let √x = t
differentiate with respect to t
1/2√x . dx/dt = 1
dx = 2√x.dt

so, $\bf{\int{\frac{cos\sqrt{x}}{\sqrt{x}}},dx}$ = $\bf{\int{\frac{cost}{\sqrt{x}}}\,2\sqrt{x}.dt}$
$=\bf{\int{2cost}\,dt}$
= 2sint + C
put t = √x ,
= 2sin√x + C