Integrate the function
![\huge\green\tt\frac{ \sqrt{tanx} }{sinxcosx} \huge\green\tt\frac{ \sqrt{tanx} }{sinxcosx}](https://tex.z-dn.net/?f=%5Chuge%5Cgreen%5Ctt%5Cfrac%7B+%5Csqrt%7Btanx%7D+%7D%7Bsinxcosx%7D)
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Answer:
Given
\begin{gathered}\sf\frac{ \sqrt{tan\:x} }{sin\:x\:cos\:x}\\ \\\end{gathered}
sinxcosx
tanx
We Doing
Simplify the Equation
Solution
Your Solution in the above picture !
Some Basics about our question
☞ Sin is equal to the side opposite the angle that you are conducting the functions on over the hypotenuse which is the longest side in the triangle.
☞ Cos is adjacent over hypotenuse.
☞ Tan is opposite over adjacent, which means tan is sin/cos. this can be proved with some basic algebra.
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