integrate the function √x with respect to X and find within the limits x=2 to 4
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:-
∫⁴ √x dx = ∫⁴ (x^½) dx
² ²
= x^(½ + 1) ˥⁴
(½ + 1) │ by the Power Rule for Integration and by the
˩² Fundamental Theorem of Calculus for definite
integration
= x^(3/2) ˥⁴
(3/2) │
˩²
= (2/3)x^(3/2)˥⁴
˩²
= (2/3)4^(3/2) ― (2/3)2^(3/2) by the Fundamental
Theorem of Calculus
for definite integration
= (2/3)[4^(3/2) ― 2^(3/2)]
= (2/3)(√4³ ― √2³)
= (2/3)(√64 ― √8 )
= (2/3){8 ― √[4(2)]}
= (2/3)(8 ― √4√2)
= (2/3)(8 ― 2√2)
= (2/3)(2)(4 ― √2)
= (4/3)(4 ― √2) or
= 3.44772 (rounded to 5 decimal places)
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2|4x−−√dx=[23xx−−√]42
=4(4−2–√)3
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