Question

Integrate the given function w.r.t. respective variable : sin² x

Answer 1

ingration of sin^2x=x/2-sin2x/4+C

Answer 2

Answer:

$\int\:sin^{2}x\:dx=\frac{x}{2} -\frac{sin\:2x}{4} +C$

Step-by-step explanation:

We know that before integrating any function ,we must convert it into integrable form.

As we know that

$cos\:2x=1-2sin^{2}x\\ \\ sin^{2}x=\frac{1-cos\:2x}{2}$

Now we can integrate it

$\int\frac{1-cos\:2x}{2}dx\\ \\ \\ = \int\frac{1}{2} dx-\frac{1}{2} \int\:cos\:2x\:dx\\ \\ \\ =\frac{x}{2} -\frac{sin\:2x}{4} +C$