Integrate this equation..
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break nom. by middle trem factor then you will find your ans automatically thanku .
abhikumar12:
at firsg break the num. dude
then you will automatically find the way to solve it.
I tried, that’s what I’m saying it is not factorisable
Can u factorise it and tell me the equation
I tried factorising it but I was unsuccessful
Or do u mean break the numerator in different parts?
yeah break the num.
Like 2x/denominator + x/denominator + 1/denominator?
no
Can u tell me the equation after breaking the numerator like just tell me the numerator after breaking it
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Answer:
Step-by-step explanation:
∫2x^2+x+1 dx/(x+1)^2(x+2)
this can be solved using integration by partial fractions
2x^2+x+1 / (x+1)^2(x+2) = a/x+1 + b/(x+1)^2 + c/ x+2
2x^2+x+1 =a(x+1)(x+2) + b(x+2) + c(x+3)^2
put x= -2
7=c
put x=-3
16=2a-b
a+c=2
a=-5
16=2a-b
16=-10-b
-26=b
∫a/x+1 + ∫b/(x+1)^2 + ∫c / x+2
∫-5 dx /x+1 +∫-26 dx /(x+1)^2 + ∫7 dx/x+2
-5∫dx/x+1 -26∫dx/(x+1)^2 +7∫dx/x+2
-5ln x+1 +26/x+1 +7 ln x+2
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