Question

integrate value of x²dx from 1/2 to-1/2​

Answer 1

Answer:

The answer is -1/12.

Explanation:

I hope it is helpfull.

Answer 2

$integral \: ( {x}^{2} \: dx) from \: 1/2 \: to \: -1/2 \\ = ( \frac{ {x}^{3} }{3} ) \: from \: \frac{1}{2} \: to \: \frac{ - 1}{2} \\ = {(\frac{1}{2} )}^{3} \times \frac{1}{3} \: - {( \frac{ - 1}{2}) }^{3} \times \frac{1}{3} \\ = \frac{1}{24} + \frac{1}{24} = \frac{1}{12}$

hope this helps you.

${\red{\boxed{MARK \:AS \: BRAINLIEST}}}$

give thanks and follow me