Question

integrate w.r.t.x
${x}^{2} - 4x + 3$
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Answer 1

Answer:

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Answer 2

❏ Question:-

•Integrate it with respect to x ;

$\int (x{}^{2}-4x+3)\, dx$

❏ Solution:-

❚❚❚➝

$\sf\longrightarrow\int (x{}^{2}-4x+3)\, dx$

$\sf\longrightarrow\int x{}^{2}\, dx-\int4x\, dx+\int3\, dx$

$\sf\longrightarrow\int x{}^{2}\, dx-4\int x\, dx+3\int\, dx$

$\sf\longrightarrow \frac{x{}^{2+1}}{2+1}-4\times\frac{x{}^{1+1}}{1+1}+3x+c$

$\sf\longrightarrow \frac{x{}^{3}}{3}-\frac{\cancel4x{}^{2}}{\cancel2}+3x+c$

$\sf\longrightarrow \boxed{\large{\red{\frac{x{}^{3}}{3}-2x{}^{2}+3x+c}}}$

where, c = integral constant.

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