Question

integrate (x+1)dy if y=6x^2

Answer 1

Here is your solution

Answer 2

Answer:

$4 x^{3}+6 x^{2}$

Step-by-step explanation:

Concept

• In mathematics, an integro-differential equation is an equation that involves both integrals and derivatives of a function.

Given

y=6$x^{2}$

Find

Integrate (x+1)dy

Solution

$\Rightarrow d y=12 x d x$

Putting value

$\int(x+1) 12 x \cdot d x$

$= \int\left(12 x^{2}+12 x\right) d x$

$= \int \frac{1}{3} \cdot 1 / 2 x^{3}+\frac{1}{1} \cdot 12 x^{2}$

$= 4 x^{3}+6 x^{2}$

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