Math, asked by bharatchawlanotecoun, 8 months ago

integrate √x/1-x dx​

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Answered by susheebalaji
0

Answer:- Here is your answer:-

Here we have (1−x)x−−√=x−−√−xx−−√=x12−x32

Hence ∫(1−x)x−−√dx

=x3232−x5252

=2xx√3−2x2x√5+C

= 2xx√(5−3x)15 +C

where C is any constant.

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