integrate √x/1-x dx
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Answer:- Here is your answer:-
Here we have (1−x)x−−√=x−−√−xx−−√=x12−x32
Hence ∫(1−x)x−−√dx
=x3232−x5252
=2xx√3−2x2x√5+C
= 2xx√(5−3x)15 +C
where C is any constant.
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