Question

integrate (x+1/x) whole cube​

Answer 1

Explanation:

∫ (x+1/x)^3 dx

=∫ [(x^3)+(1/x^3)+{3.x^2.(1/x)}+{3.x.(1/x^2)}] dx

=∫x^3+1/x^3+3x+3/x dX

=x^4/4+{x^(-2)/(-2)} +3x^2/2+3lnx+c

=x^4/4-1/2x^2+3x^2/2+3lnx+c

answer