integrate (x^2+4)/(x^4+16)
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Answered by
2
Step 1: divide numerator and
denominator by [math]x^2[/math].
Step 2:write denominator as
[math](x-4/x)^2 +8[/math]
Step 3: take x-4/x as t. We get dt =
[math](1+4/x^2) .dx[/math] which is
numerator. We get
[math]dt/t^2 + 2√2^2[/math]
Step 4: we get tan inverse t/2√2
multiplied by 1/4√2
i think it's help your
then pls mark brainliest answer
denominator by [math]x^2[/math].
Step 2:write denominator as
[math](x-4/x)^2 +8[/math]
Step 3: take x-4/x as t. We get dt =
[math](1+4/x^2) .dx[/math] which is
numerator. We get
[math]dt/t^2 + 2√2^2[/math]
Step 4: we get tan inverse t/2√2
multiplied by 1/4√2
i think it's help your
then pls mark brainliest answer
Answered by
1
Sorry for the handwriting mess...
Hope I helped u and this is ur required answer.
Hope I helped u and this is ur required answer.
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