integrate (x+2)/(x^2-3x+2)
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(x+2)÷(x²-3x+2)
=> (x+2)÷[x²-(2+1)x+2]
=> (x+2)÷[x²-2x-x+2]
=> (x+2)÷[x(x-2)-1(x-2)]
=>(x+2)÷(x-2)(x-1)
I hope this will help you
(-:
=> (x+2)÷[x²-(2+1)x+2]
=> (x+2)÷[x²-2x-x+2]
=> (x+2)÷[x(x-2)-1(x-2)]
=>(x+2)÷(x-2)(x-1)
I hope this will help you
(-:
debanjaliy:
after that...
hi
pls send the full sum
This is full
no the sum is integration
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