Question

integrate( x^3+8)(x-1)/(x^2-2x+4)​

Answer 1

I=∫ (x 2−2x+4) (x 3 +8)(x−1)

dx=∫ (x 2 −2x+4)(x 3 +(2) ( 3 )(x−1)

dx=∫ (x2 −2x+4)(x+2)(x 2 +4−2x)(x−1)

dx

=∫(x+2)(x−1)dx=∫x 2+x−2dx

= 3×3 + 2×2 −2x+c

Hope it helps you....